#Peg solitaire solver u shape code
#Peg solitaire solver u shape plus

Next, using the 1d X, Y and Z positions solve changes each of those positions on the board to 0, 0 and 1 respectively to simulate the jump, and recuses with the new board and the old board stored in a list, and 1 removed from the pegs on board count. If the quit is 1, it reaches the base case and exits with the Y and Z positions converted into 1d form, otherwise it recuses into the next direction. If the Y peg is 1 and the Z peg is 0, the program changes a quit variable to 1, otherwise it leaves it 0. Else, can jump takes the row and col for both the Y peg and Z peg, and uses the 2dindexfinder method to find the peg at that position. It then returns the 2d positions with the offsets for the asked direction, but if the row or col are off the board, it returns the 2d row and col of the current X peg position, because that will fail the rest of canjump. The canjump then sends the direction variable to getrowandcol, which has hardcoded offset 2d values for each 8 directions. The solve method calls canjump with the direction variable as 1. The biggest thing in here is the creation of the canjump method, which, using the getrowandcol method, checks for jumpable positions on the board. each of the 2R circle positions is covered by at least one card that has no hole punched out there.Peg solitaire solver in Prolog that solves any shaped board, and can output inverted solutions and failure solutions Your puzzle is to see if you can place all the cards in the box (each one either gray-side-up or white-side-up) so as to completely cover the bottom of the box, i.e. Each card contains 2R circles lined up in two columns and R rows, each of which may be punched out (so it is a hole) or not. Because of the asymmetric shapes of the cards, which exactly match the shape of the hole in the box, each card will fit in the box in only two possible ways (gray-side-up or white-side-up).

Each card is blue on one side, white on the other.

#Peg solitaire solver u shape code

Note: From the Obfuscated C code contest. One of these numbers repeats itself once in the sequence. You are given a sequence S of numbers whose values range from 1 to n-1. (As always, there are both smart and stupid ways to do this. Write a little program that accepts as input a string, and outputs a boolean value telling whether or not the input is a palindrome. Note: 'Constant memory' = the memory required for the solution cannot be a function of n. Using a constant amount of memory, find a loop in a singly-linked list in O(n) time.

#Peg solitaire solver u shape plus

Plus or minus signs can be considered non-numeric characters. If pStr contains non-numeric characters, either return 0 (ok) or return the number derived so far (better) (e.g. Write the definition for the atoi (ASCII to integer) function without using any built-in functions. Now devise a way to find an element in the rotated array in O(log n) time. So for instance, 1 2 3 4 5 might become 3 4 5 1 2. But suppose I rotate the sorted array at some pivot unknown to you beforehand. Latest additions to cover site can be seen by clicking here.Īn element in a sorted array can be found in O(log n) time via binary search. RECENT ADDITIONS Check out latest puzzles by perusing the forum and the 10 most recent posts. Thousands of posts by really clever people. Want to test-drive a new riddle of your own? I don't know the solution to this problem myself. Needs math past arithmetic and basic probability. Page last modified Friday, 1 19:30:38 PST